Question

determine a soma dos infinitos termos (5, 5/2,5/4,...)

Answer 1

Resposta:

Explicação passo a passo:

PG (5, 5/2,5/4,...)

$a_{1} =5\\\\r=\frac{1}{2}$

Soma dos termos de uma PG infinita

$S_{n} =\frac{a_1}{1-q} \\\\S_{n} =\frac{5}{1-\frac{1}{2} } \\\\S_{n} =\frac{5}{\frac{1}{2} }\\\\S_{n}=5*\frac{2}{1} \\\\S_{n}=10$

Answer 2

Resposta:

Sn=10

Explicação passo-a-passo:

$a1 = 5$

$r = \frac{a2}{a1} = \frac{5}{2} \div 5 = \frac{5}{2} \times \frac{1}{5} = \frac{5}{10} = \frac{1}{2}$

$sn = \frac{1}{1 - q}$

$sn = \frac{5}{1 - \frac{1}{2} } = \frac{5}{ \frac{1}{2} } = 5\times 2 = 10$