Question

determine a soma da pg infinita (1/3+1/9+1/27+...)

Answer 1

S = a1/ ( 1 - q)

a1 = 1/3
a2 = 1/9

q = 1/9 : 1/3 = 1/9 * 3/1 = 3/9  = 1/3 ***

S = (1/3)/ ( 1/1 - 1/3 )
S = 1/3 : 2/3  ou   1/3 *  3/2 = 3/6 =  1/2 ***resposta