Question

determine a soma da P.G. infinita (1/3 + 2/9 2/27 + ...)

Answer 1

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Ola Gabi

PG 

u1 = 2/9
u2 = 2/27

q = u2/u1 = (2/27)/(2/9) = (2/27)*(9/2) = 1/3 

soma infinita
Sn = u1/(1 - q)
Sn = (2/9)/(1 - 1/3) = (2/9)/(2/3) = (2/9)*(3/2) = 1/3

soma
1/3 + 1/3 = 2/3

pronto