Question

Determine a soma algébrica sob a forma de fração irredutível.
A 4/5 + 2 - 1/4
B 1/3 - 1/2 + 5/6 - 8/3
C 7 - ( 1 - 4/3)
D -7/12 + ( -4/15 + 2) - ( 7/6 - 3/4)
E | - 1/2 + 1/3 |
F 2,5 - ( - 3/2 - 2)
G 0,01 + ( - 1/200 ) + 1,03
H | - 5 + 7/20 - 32/10 |
Por favor é para hoje!​

Answer 1

Resposta:

Leia abaixo

Explicação passo-a-passo:

$\dfrac{4}{5} + 2 - \dfrac{1}{4} = \dfrac{16 + 40 - 5}{20} = \dfrac{51}{20}$

$\dfrac{1}{3} - \dfrac{1}{2} + \dfrac{5}{6} - \dfrac{8}{3} = \dfrac{2 - 3 + 5 - 16}{6} = -2$

$7 - ( 1 - \dfrac{4}{3}) = \dfrac{21 - 3 + 4}{3} = \dfrac{22}{3}$

$-\dfrac{7}{12} + ( -\dfrac{4}{15} + 2) - ( \dfrac{7}{6} - \dfrac{3}{4}) = -\dfrac{7}{12} + \dfrac{26}{15} - \dfrac{5}{12} = \dfrac{-35 + 104 - 25}{60} = \dfrac{11}{15}$

$|-\dfrac{1}{2} + \dfrac{1}{3}\:\:| = \dfrac{-3 + 2}{6} = |-\dfrac{1}{6} \: \: | = \dfrac{1}{6}$

$2,5 - ( - \dfrac{3}{2} - 2) = \dfrac{25}{10} - ( - \dfrac{7}{2}) = \dfrac{25 + 35}{10} = 6$

$0,01 + ( - \dfrac{1}{200} ) + 1,03 = \dfrac{1}{100} - \dfrac{1}{200} + \dfrac{103}{100} = \dfrac{2 - 1 + 206}{100} = \dfrac{207}{100}$

$|- 5 + \dfrac{7}{20} - \dfrac{32}{10} \:\:|= \dfrac{-100 + 7 - 64}{20} = |-\dfrac{157}{20}\:\: | = \dfrac{157}{20}$