Matemática, perguntado por davidjhuan12, 4 meses atrás

Determine a raiz de cada equação a seguir (resolva descobrindo o valor do termo x desconhecido). a)x-17 = -9 b)2x = -7 c)3x+2 = 2x-11 d)2x = 16 e)x/2 = -5 f)2x+14 = 5x-1 g)4x-5 =6x+11 h)5x+4-2x = 26-3x i)3.(x+2)+5 = x+12 j)x+4.(x-1) = 9-2.(x+3) k)5.(3x-2) = 2.(6x+3) l)2.(3x-1)+2.(3-x) m)7.(x-1) = 2.(3x+1) n)2.(3-y)+7.(2-y) = 15-4y o)2.(x-2)+5.(2-x)+6.(x-1) = 0 p)3.(x-2)-(1-x) = 13

Soluções para a tarefa

Respondido por tamiressouto2001
1

Resposta:

a) 8    

b) -3,5  

c) -9  

d) 9,5    

e) -10    

f) -5    

g) -2    

h) 3,66...

i) 0,5    

j) 1                

k) 5,33...    

l) 5x+4

m) 9

n) -1

o) 0

p)

Explicação passo a passo:

a)x-17 = -9

x=17-9

x=8

b)2x = -7

x=-7÷2

x=-3,5

c)3x+2 = 2x-11

3x-2x=2-11

x=-9

d)2x = 16

x=19÷2

x=9,5

e)x/2 = -5

x=-5.2

x=-10

f)2x+14 = 5x-1

2x-5x=-1-14

-3x=-15

x= -15÷3

x=-5

g)4x-5 =6x+11

4x-6x=11-5

-2x=6

x=6÷(-3)

x=-2

h)5x+4-2x = 26-3x

5x-2x+3x=26-4

6x=22

x=22÷6

x= 3,66...

i)3.(x+2)+5 = x+12

3x+6+5=x+12

3x-x=12-6-5

2x= 1

x= 1÷2

x=0,5

j)x+4.(x-1) = 9-2.(x+3)

x+4x-4=9-2x-6

x+4x+2x=9-6+4

7x=7

x=7÷7

x=1

k)5.(3x-2) = 2.(6x+3)

15x-10=12x+6

15x-12x=6+10

3x=16

x=16÷3

x=5,33...

l)2.(3x-1)+2.(3-x)

6x-2+6-x

5x+4

m)7.(x-1) = 2.(3x+1)

7x-7=6x+2

7x-6x=2+7

x=9

n)2.(3-y)+7.(2-y) = 15-4y

6-2y+14-7y=15-4y

-2y-7y+4y=15-6-14

-5y=-5

y=-5÷5

y=-1

o)2.(x-2)+5.(2-x)+6.(x-1) = 0

2x-4+10-5x+6x-6=0

3x=0

x=0÷3

x=0

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