Question

Determine a medida de x
110°
50°
C

Answer 1

$\Large\boxed{\begin{array}{l}\sf Seja\,\theta\,o\,3^o\,\hat angulo\,desse\,tri\hat angulo.\\\sf \theta+50^\circ+110^\circ=180^\circ\\\sf \theta+160^\circ=180^\circ\\\sf \theta=180^\circ-160^\circ\\\sf\theta=20^\circ\end{array}}$

$\Large\boxed{\begin{array}{l}\underline{\rm Pela\,lei\,dos\,senos\,temos:}\\\sf\dfrac{x}{sen(50^\circ)}^=\dfrac{110}{sen(20^\circ)}\\\\\sf x\cdot sen(20^\circ)=110\cdot sen(50^\circ)\\\sf x\cdot0,34=110\cdot0,76\\\sf 0,34x=83,6\\\sf x=\dfrac{83,6}{0,34}\\\\\sf x=245,88\,m\checkmark\end{array}}$