Question

Determine a massa presente em 5 mols de Cromato de Manganês - Mn(CrO4)2

Answer 1

1 mol Mn(CrO8)2____287
5mol ______X
X=1435g

Answer 2

1 mol Mn(CrO4)2-----------------------201g
5mol Mn(crO4)--------------------------Xg=

5 x 201/1=1001g
Mn=25g
Cr=24g
O=16

(CrO4)2= (24+16x4)2=176g
Mn=25g
_______________________
201g