Question

Determine a massa de ferro que pode ser obtida a partir de 1000 t (toneladas) de hematita contendo 80% de Fe²O³.

Dados: Fe²O³=160g/mol
CO=28g/mol
Fe=56g/mol
CO²=44g/mol.

Fe²O³(s)+3 CO(g)---> 2 Fe(s)+ 3 CO²(s)

Answer 1

$\Large\boxed{\begin{array}{l}\sf 1000\,ton=1000\,000\,kg=1000\,000\,000=10^9\,g\\\sf Fe_2O_3+3CO\longrightarrow 2Fe+3CO_2\\\sf 160\,g\,de\,Fe_2O_3\longrightarrow 112\,g\,de\,Fe\\\sf 10^9\,g\longrightarrow x\\\sf 160x=112\cdot10^9\\\sf x=\dfrac{112\cdot10^9}{160}\\\\\sf x=0,7\cdot10^9\\\\\sf x=7\cdot10^8\,g \end{array}}$

$\Large\boxed{\begin{array}{l}\sf 7\cdot10^8\longrightarrow 100\%\\\sf y \longrightarrow 80\%\\\sf 100y=80\cdot7\cdot10^8\\\sf 100y=560\cdot10^8\\\sf y=\dfrac{560\cdot10^8}{100}\\\\\sf y=5,6\cdot10^8\,g\,de\,Fe_2\end{array}}$