Question

Determine:

a)log15 3 + log15 5

b)log3 72 - log 3 12 - log3 2

sabendo que log2>0,301 e log3=0,477,determine:

a)log6

b)log48

Answer 1

Determine:

a)log₁₅3 + log₁₅ 5  = log₁₅ (3*5) =log₁₅ 15 = 1

b) log₃ 72 - log₃ 12 - log₃ 2 =log₃ (72)/12 - log₃ 2 = log₃ 6 -  log₃ 2

=log₃ (6/2) = log₃ 3 = 1

***sabendo que log2=0,301 e log3=0,477,determine:

a) log6 = log 2*3 = log 2 + log 3 = 0,301 +0,477 = 0,778

b) log 48 = log 2⁴*3 = log 2⁴ + log 3 = 4 *log 2+ log 3 = 4*0,301+0,477

=1,681