Question

determine a fraçao geratriz da dizima periodica 0,12525...a)124/990b)125/999c)125/990d)25/99

Answer 1

X = 0,12525... (×10)
10X = 1,2525...
10X = 1 + 0,2525...
10X = 1 + 25/99 (×99)
990X = 99 + 25
990X = 124
X = 124 / 990

Alternativa (A) 124/990

Answer 2

x=0,12525>>>>×10
10x=1,2525
10x = 1 + 0,2525
10x=1+25/99>>>>×99
990x==99+25
990x=124
x=124/990

determine a fraçao geratriz da dizima periodica
R: 124/990