Question

Determine a equação do 2° grau, sabendo que sias raízes são:
:(a): 5 e 7 :(b): -8 e -5

Answer 1

$S=(5;7)\\\\\\(x-x')(x-x'')\to \\\\ (x-5)(x-7)\to \\\\ x^{2} -5x-7x+35=0\to \\\\ x^{2} -12x+35=0$




$S=(-8;-5)\\\\\\(x-x')(x-x'')\to \\\\ (x-(-8))(x-(-5))\to (x+8)(x+5)\to \\\\ x^{2} +5x+8x+40=0\to \\\\ x^{2} +13x+40=0$