Question

Determine a coordenada dos ponto medio do segmento ab conhecendo se A (3,-2) B (0,1) , e A (-2,5) B (-8,7)

Answer 1

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Solução!


$A (3,-2)\\\\ B (0,1)$


$M_{(A,B)} =\left ( \dfrac{ x_{A}+ x_{B} }{2}, \dfrac{y_{A}+y_{B} }{2} \right ) \\\\\\\\\\ M_{(A,B)} =\left ( \dfrac{ 3+ 0 }{2}, \dfrac{-2+1 }{2} \right ) \\\\\\\\ M_{(A,B)} =\left ( \dfrac{ 3 }{2}, \dfrac{-1 }{2} \right )$




$A (-2,5) \\\\\ B (-8,7)$

$M_{(A,B)} =\left ( \dfrac{ x_{A}+ x_{B} }{2}, \dfrac{y_{A}+y_{B} }{2} \right )\\\\\\\\\ M_{(A,B)} =\left ( \dfrac{ -2-8 }{2}, \dfrac{5+7 }{2} \right )\\\\\\\\ M_{(A,B)} =\left ( \dfrac{ -10 }{2}, \dfrac{12 }{2} \right )\\\\\\\\ M_{(A,B)} =(-5,6)$

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