Question

Determine a base e a altura. Quero o calculo

Answer 1

$(3x + 5)(3x - 5) = 100 \\ 9x^2 - 25 = 100 \\ 9x^2 = 100 + 25 \\ 9x^2 = 125 \\ \\ x^2 = \frac{125}{9} \\ \\ x = \sqrt{ \frac{125}{9} } \\ \\ x = \frac{5 \sqrt{5} }{3}$

$C = 3(\frac{5 \sqrt{5} }{3}) + 5 ==\ \textgreater \ 5 \sqrt{5} + 5 \\ \\ C = 5( \sqrt{5} + 1)cm \\ \\ L = 3(= \frac{5 \sqrt{5} }{3}) - 5 ===\ \textgreater \ 5 \sqrt{5} - 5 \\ \\ L = 5( \sqrt{5} - 1)cm$