Question

Determine 31° termo da PG (4,6,9...)

Answer 1

$q= \frac{a_2}{a_1}= \frac{6}{4} = \frac{3}{2}$
$a_{31}=a_1\cdot q^{30}$
$a_{31}=4\cdot (\frac{3}{2}) ^{30}$
$a_{31}=2^2\cdot (\frac{3}{2}) ^{30}$
$a_{31}=\frac{3^{30}}{2^{28}}$