Question

determine 10 termo da pg (3,6,12)

Answer 1

$a_n = a_1 \times q^{n-1} \\a_{10} = 3 \times 2^{10-1} \\ a_{10} = 3\times 2^9 \\ a_{10} = 3\times 512 \\ a_{10} = 1536$