Question

DETERMINAR O VERTICES AS RAIZES DA EQUAÇAO (X1 E X2) A- X²+3x+2B- X²-X-20C- X²+6x+8D- X²-4

Answer 1

Oi Carlelisa

a) 

x² + 3x + 2 = 0 

delta
d² = 9 - 8 = 1
d = 1

x1 = (-3 + 1)/2 = -2/2 = -1
x2 = (-3 - 1)/2 = -4/2 = -2

vértice

Vx = -b/2a = -3/2
Vy = -d²/4a = -1/4 

b)

x² - x - 20 = 0

delta
d² = 1 + 80 = 81
d = 9

x1 = (1 + 9)/2 = 10/2 = 5
x2 = (1 - 9)/2 = -8/2 = -4

vertice

Vx = -b/2a = 1/2
Vy = -d²/4a = -81/4 

c) 

x² + 6x + 8 = 0

delta
d² = 36 - 32 = 4
d = 2

x1 = (-6 + 2)/2 = -4/2 = -2
x2 = (-6 - 2)/2  = -8/2 = -4

vértice

Vx = -b/2a = -6/2 = -3
Vy = -d²/4a = -4/4 = -1

d)

x² - 4 = 0
x² = 4

delta
d² = 16
d = 4

x1 = 4/2 = 2
x2 = -4/2 = -2

vértice

Vx = -b/2a = 0
Vy = -d²/4a = -16/4 = -4 

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