Question

Determinar o valor, caso exista:
lim x²-y²/1+x²+y²
(x,y)(0,0)

Answer 1

Lim (x²-y²)/(1+x²+y²)

(x,y)-->(0,0)

=

Lim x²/(1+x²+y²)  -  Lim y²/(1+x²+y²)

(x,y)-->(0,0)        (x,y)-->(0,0)

= 0/(1+0+0)  - 0/(1+0+0)

=0  - 0 = 0