Question

Determinar a Massa Molecular:
a) Li Br b) Mg Br₂

c) Ca (NO₃)₂ d) C₆ H₁₂ O₆

e) Ca (OH)₂ f) K₃ PO₄

Answer 1

a)Li Br= 6,94+79,90=86,8
b)Mg Br2= 24,31+(2.79,90)=24,31+159,8=184,1
c)Ca(NO3)2= 40,08+(14.2)+(16.6) = 40+28+96 = 164
d)C6H12O6= (6.12)+(12.1)+(6.16)=72+12+96=180
e)Ca(OH)2= 40,08. (2.16)+(2.1) = 40+32+2 = 74
f)K3PO4= (3.39,1)+30,97+(4.16) = 117,3+31+64= 212,3