Question

descubra os valores de x, utilizando o teorema de Pitágoras​

Answer 1

Resposta:

Explicação passo-a-passo:

a) $(2x)^2=x^2+(3\sqrt3)^2\\4x^2=x^2+9.3\\4x^2-x^2=27\\3x^2=27\\x^2=\frac{27}{3}\\x^2=9\\x=\sqrt9\\x=3$

b)$x^2=5^2+5^2\\x^2=25+25\\x^2=50\\x=\sqrt{50}\\x=\sqrt{25.2}\\x=5\sqrt2$

c) $20^2=(3x)^2+(4x)^2\\400=9x^2+16x^2\\400=25x^2\\x^2=\frac{400}{25}\\x^2=16\\x=\sqrt{16}\\x=4$