Question

Descubra o valor de x:

Answer 1

a) Sen 30 = x/20

1/2 = x/20

2x = 20

x = 20/2 = 10

x = 10

b) Cos45 = x/6

$\dfrac{\sqrt{2}}{2}= \dfrac{x}{6}$

$6\sqrt{2} = 2x$

$x = \dfrac{6\sqrt{2}}{2}= 3\sqrt{2}$

$x = 3\sqrt{2}$

c) Acho que vc colocou os angulos ao contrario....

$cos60 = \frac{x}{10\sqrt{3} }$

$\frac{1}{2} = \frac{x}{10\sqrt{3} }$

$2x = 10\sqrt{3}$

$x = \frac{10\sqrt{3}}{2} = 5\sqrt{3}$

$x = 5\sqrt{3}$

Answer 2

Vamos la

a)  pelo senos temos

sen(30) = x/20

1/2 = x/20

2x = 20

x = 20/2 = 10

b) pelo cossenos temos

cos(45) = x/6

√2/2 = x/6

2x = 6√2

x = 3√2

c) pelo cossenos temos

cos(60) = x/(10√3)

1/2 = x/(10√3)

2x = 10√3

x  = 5√3