Question

Dertermine a intensidade do campo elétrico gerado a 0,20m de uma carga elétrica puntiforme q = 4.10-8C, no vácuo.

Answer 1

$E=k.\frac{Q}{d^{2}}\\E=9.10^{9}(\frac{N.m^{2}}{C^{2}}).\frac{4.10^{-8}C}{0,2m^{2}}\implies E=9.10^{9}(\frac{N.m^{2}}{C^{2}}).\frac{4.10^{-8}C}{0,04m^{2}}\implies \\\\ E=9.10^{9}(\frac{N}{C}).\frac{4.10^{-8}}{0,04}\implies E=9.10^{9}(\frac{N}{C}).\frac{4.10^{-8}}{4.10^{-2}}\implies \\\\ E=(\frac{N}{C}).\frac{9.10^{9}.4.10^{-8}}{4.10^{-2}}\implies E=(\frac{N}{C}).\frac{36.10^{1}}{4.10^{-2}}\implies \\\\ E=9.10^{3}N/C}$