Question

Derivada $F(t)= e^{2cos.2t}$

Answer 1

F(t) = e^2cos(2t)

F'(t) = e^2cos(2t) . (2cos(2t))' 

F'(t) = e^2cos(2t) . 2(-sen(2t). 2(t)') 

F'(t) = 4.e^2cos(2t) (-sen(2t))

*-*-*-*-*-*-*-*-*-*-*-*
16/10/2016
Sepauto
SSRC
*-*-*-*-*-*-*-*-*-*-*-*

Answer 2

$\mathsf{f(t)=e^{2cos(2t)}}\\\mathsf{f'(t)=e^{2cos(2t)}.-4sen(2t)}$