Question

Derivada log 2 x qual é?

Answer 1

Se a base for 10, temos :

y = log2x → y' = ( 2(x)' )/2x×ln10

y' = 2/(2x×ln10)

Se a base for 2, temos :
y = log2 x
y' = x'/(x×ln2)

y' = 1/(x×ln2)