Question

Derivada de
$y=x^5senx$

Answer 1

y = x⁵senx

y' = (x⁵)'Senx + X⁵(Senx)'

y' = 5x⁴Senx + x⁵Cosx

y' = x⁴( 5*Senx+x*Cosx)

Answer 2

$\sf \displaystyle y=x^5\:sen\:x\\\\\\\frac{d}{dx}\left(x^5\sin \left(x\right)\right)\\\\\\=\frac{d}{dx}\left(x^5\right)\sin \left(x\right)+\frac{d}{dx}\left(\sin \left(x\right)\right)x^5\\\\\\\to \boxed{\sf =5x^4\sin \left(x\right)+\cos \left(x\right)x^5}$