Derivada da função f(×)=(x-3)²
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Faça pela regra da cadeia.
derive fora, conserve dentro e multiplique pela derivada interna.
![\\ F(x) = (x-3)^2
\\
\\ F(x)' = [(x-3)^2]'*(x-3)'
\\
\\ F(x)' = 2(x-3)^2^-^1(1-0)
\\
\\ F(x)' = 2(x-3)^1*1
\\
\\ F(x)' = 2(x-3)](https://tex.z-dn.net/?f=+%5C%5C+F%28x%29+%3D+%28x-3%29%5E2%0A+%5C%5C+%0A+%5C%5C+F%28x%29%27+%3D+%5B%28x-3%29%5E2%5D%27%2A%28x-3%29%27%0A+%5C%5C+%0A+%5C%5C+F%28x%29%27+%3D+2%28x-3%29%5E2%5E-%5E1%281-0%29%0A+%5C%5C+%0A+%5C%5C+F%28x%29%27+%3D+2%28x-3%29%5E1%2A1%0A+%5C%5C+%0A+%5C%5C+F%28x%29%27+%3D+2%28x-3%29 "\\ F(x) = (x-3)^2
\\
\\ F(x)' = [(x-3)^2]'*(x-3)'
\\
\\ F(x)' = 2(x-3)^2^-^1(1-0)
\\
\\ F(x)' = 2(x-3)^1*1
\\
\\ F(x)' = 2(x-3)")
derive fora, conserve dentro e multiplique pela derivada interna.
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