Question

defina o logaritimo
a) log 4 √32
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Answer 1

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\mathsf{log_4\:\sqrt{32} = x}$

$\mathsf{4^x = \sqrt{32}}$

$\mathsf{(2^2)^x = \sqrt{2^5}}$

$\mathsf{2^{2x} = 2^{\frac{5}{2}}}$

$\mathsf{2x = \dfrac{5}{2}}$

$\boxed{\boxed{\mathsf{x = \dfrac{5}{4}}}}$