de quantas maneiras podemos extrair 4 cartas de um baralho de 52 cartas ?
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Também é uma combinação, no caso, de 52 elementos tomados 4 a 4
![C_{52,4}=\frac{52!}{4!(52-4)!}\\\\C_{52,4}=\frac{52!}{4!48!}\\\\C_{52,4}=\frac{52*51*50*49*48!}{4*3*2*148!}\\\\C_{52,4}=\frac{52*51*50*49}{4*3*2}\\\\C_{52,4}=13*17*25*49\\C_{52,4}=270725 C_{52,4}=\frac{52!}{4!(52-4)!}\\\\C_{52,4}=\frac{52!}{4!48!}\\\\C_{52,4}=\frac{52*51*50*49*48!}{4*3*2*148!}\\\\C_{52,4}=\frac{52*51*50*49}{4*3*2}\\\\C_{52,4}=13*17*25*49\\C_{52,4}=270725](https://tex.z-dn.net/?f=C_%7B52%2C4%7D%3D%5Cfrac%7B52%21%7D%7B4%21%2852-4%29%21%7D%5C%5C%5C%5CC_%7B52%2C4%7D%3D%5Cfrac%7B52%21%7D%7B4%2148%21%7D%5C%5C%5C%5CC_%7B52%2C4%7D%3D%5Cfrac%7B52%2A51%2A50%2A49%2A48%21%7D%7B4%2A3%2A2%2A148%21%7D%5C%5C%5C%5CC_%7B52%2C4%7D%3D%5Cfrac%7B52%2A51%2A50%2A49%7D%7B4%2A3%2A2%7D%5C%5C%5C%5CC_%7B52%2C4%7D%3D13%2A17%2A25%2A49%5C%5CC_%7B52%2C4%7D%3D270725)
patriciadaperdi:
deu a mesma resposta do livro *-*
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