Question

De o resultado de:
100-413·(20-5×4)+1
400-{10-[30÷(30-0÷17)]-1}
27+{14+3·[100÷(18-4·2)+7]}÷13
AJUDA PFV!!!​

Answer 1

$100-413\left(20-5\times \:4\right)+1\\\\=100-413\times \:0+1\\\\=100-0+1\\\\=101$             $400-10-\left[30\div \left(30-0\div \:17\right)\right]-1\\\\=400-10-1-1\\\\=388$

$27+14+3\left[100\div \left(18-4\cdot \:2\right)+7\right]\div \:13\\\\=27+14+3\cdot \:17\div \:13\\\\=27+14+\frac{51}{13}\\\\=\frac{584}{13}\\\\=44\frac{12}{13}$