Matemática, perguntado por geekwoman7876, 11 meses atrás

Dados os conjuntos


A 1,2,5,6,7,8

B 0,1,3,5.9,10

C 1,3,4,5,10,12

D 0,1,3,4,6,8


Determine

A= AxB

B= AxC

C=BxC

D=AxB

E=BxB

F=CxC

Soluções para a tarefa

Respondido por alcielerosa1
4

Olá!  Basicamente este exercício corresponde à multiplicação entre pares ordenados envolvendo conjuntos distintos, que também pode ser chamado de Produto Cartesiano.  

Dado os conjuntos:  

A = {1,2,5,6,7,8}  

B = {0,1,3,5.9,10}  

C = {1,3,4,5,10,12}  

D = {0,1,3,4,6,8}  

Vamos determinar a relação binária entre os seguintes conjuntos:  

a) AxB  

b) AxC  

c) BxC  

d) AxD  

e) BxB  

f) CxC  

E aqui estão os pares ordenados formados devido à relação dos conjuntos anteriores:

a) {(1,0),(1,1),(1,3),(1,5),(1,9),(1,10),(2,0),(2,1),(2,3),(2,5),(2,9),(2,10),(5,0),(5,1),(5,3),(5,5),(5,9),(5,10),(6,0),(6,1),(6,3),(6,5),(6,9),(6,10),(7,0),(7,1),(7,3),(7,5),(7,9),(7,10)}  

b) {(1,1),(1,3),(1,4),(1,5),(1,10),(1,12), (2,1),(2,3),(2,4),(2,5),(2,10),(2,12),(5,1),(5,3),(5,4),(5,5),(5,10),(5,12),(6,1),(6,3),(6,4),(6,5),(6,10),(6,12),(7,1),(7,3),(7,4),(7,5),(7,10),(7,12),(8,1),(8,3),(8,4),(8,5),(8,10),(8,12)}  

c) {(0,1),(0,3),(0,4),(0,5),(0,10),(0,12), (1,1),(1,3),(1,4),(1,5),(1,10),(1,12),(3,1),(3,3),(3,4),(3,5),(3,10),(3,12),,(5,1),(5,3),(5,4),(5,5),(5,10),(5,12),(9,1),(9,3),(9,4),(9,5),(9,10),(9,12),(10,1),(10,3),(10,4),(10,5),(10,10),(10,12)}  

d) {(1,0),(1,1),(1,3),(1,4),(1,6),(1,8),(2,0),(2,1),(2,3),(2,4),(2,6),(2,8),(5,0),(5,1),(5,3),(5,4),(5,6),(5,8),(6,0),(6,1),(6,3),(6,4),(6,6),(6,8),(1,0),(7,1),(7,3),(7,4),(7,6),(7,8),(8,0),(8,1),(8,3),(8,4),(8,6),(8,8)}  

e) {(0,0),(0,1),(0,3),(0,5),(0,9),(0,10),(1,0),(1,1),(1,3),(1,5),(1,9),(1,10),(3,0),(3,1),(3,3),(3,5),(3,9),(3,10),(5,0),(5,1),(5,3),(5,5),(5,9),(5,10),(9,0),(9,1),(9,3),(9,5),(9,9),(9,10),(10,0),(10,1),(10,3),(10,5),(10,9),(10,10)}  

f) {(1,1),(1,3),(1,4),(1,5),(1,10),(1,12), (3,1),(3,3),(3,4),(3,5),(3,10),(3,12),(4,1),(4,3),(4,4),(4,5),(4,10),(4,12),(5,1),(5,3),(5,4),(5,5),(5,10),(5,12),(10,1),(10,3),(10,4),(10,5),(10,10),(10,12),(12,1),(12,3),(12,4),(12,5),(12,10),(12,12)}

Abraços!!

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