Question

Dados log2 = 0,3 e log3 =0,48 , qual log raiz de 1200

Answer 1

Log √1200

= Log 1200^1/2
= 1/2 Log 2^4 * 3 * 5^2
= 1/2 ( 4Log2 + Log 3 + 2 Log5)
= 1/2 ( 4*0,3 + 0,48 + 2*0,7)
= 1/2 (1,2 + 0,48 + 1,4)
= 1/2 (3,08)
= 1,54