Question

Dados log 2 = 0,3010
Log 3= 0,4771 e log 5= 0,6990 calcule
A) log 128
B) log 40

Answer 1

$a) Log128 = Log2^{7} Log128 = 7Log2 Log128 = 7(0,3010) Log128 = 2,107 [tex]b) Log40 = Log2^{3} .5 = 3Log2 + Log5 Log40 = 3(0,3010) + 0,6990 Log40 = 1,602$