Question

Dados log 2 = 0,301, log 3 = 0,477 e log 5 = 0,699 calcule o valor de:

Answer 1

a) log 12

= log 3*4  

=log 3+log 4

=log 3+log 2²

=log 3 +2*log 2

=0,477+2*0,301

=1,079

b) log 4/25

= log 4 - log 25

=log 2²-log 5²

=2*log 2-2 *log 5

=2 *0,301 -2*0,699

= -0,796

c)log 0,5

=log 1/2

=log 2^(-1)

=-log 2  

= -0,301

d) log 5^(2/3)

=(2/3)* 0,699

=0,466

e) log (2*3²)^(1/3)

=(1/3) * (log 2 +2* log 3)

=(1/3) *( 0,301 +2*0,477)

=0,418333