Question

Dados log 2 =0,301 e log 5 =0699; então log 20 é ingual a : a)0,301 b)2,301 c)1,301 d)0,601

Answer 1

㏒20 = ㏒ (2.10) = ㏒ 2 + ㏒10 = 0,301 + 1 = 1,301.
Alternativa C.

Answer 2

log10 = log(2*5) = log2 + log5 = 0,301+0,699
Portanto log10 = 1
log20 = log(10*2) = log10 + log2 = 1 + 0,301
Portanto log20 = 1,301 (c)
*Igual