Question

dados log 2= 0,301 e log 3 = 0,477 de o valor de :

log 12
log 125
log 3600
log 0, 0108
log $2 \sqrt{3}$

Answer 1

Dados log 2= 0,301 e log 3 = 0,477 de o valor de :

log 12==> Log(2².3) ==> 2Log2 + Log3 ==> 2.(0,301) + 0,477
 0,602 + 0,477 ==> 1,079

log 125 ==>Log 5³ ==> 3Log 5 ==> 3Log(10/2)==>3(Log10 - Log2)
3(1 - 0,301) ==> 3(0,699) ==> 2,097
 
log 3600 ==> Log(2².3²10²)
2[Log2 + Log3 + Log10]
2[0,301+ 0,477 + 1] ==> 2[1,778] ==> 3,556

log 0, 0108 ==> Log 108/10000
Log108 - log 10000
Log(2².3³) - Log10^4
2Log2 + 3Log3 - 4Log10
2(0,301) +3(0,477) - 4.1
0,602+ 1,431 - 4
 - 1,967

log (2√3)
Log2 + Log√3
Log2 + Log3^1/2
Log2 + 1Log3
              2

0,301 + 0,477
                  2
0,602 + 0,477
           2
1,079
     2