Question

Dados log 2= 0, 301 e log 3=0,477 calcule 36.

Answer 1

Se for pra calcular o log 36, então:

$36=4.9=2^2.3^2\\\\ Ent\~ao:\\\\ log36=log4.9=log4+log9=log2^2+log3^2=\\\\ 2.log2+2.log3=2.0,301+2.0,477=0,602+0,954=1,556$