Question

DadoP(x)=x3 +x2 +x+4,calculeP(0)+P(1)+P(2)–3P(-1)

Answer 1

Resposta:

P(x) = x³ + x² + x + 4

P(0) = 0³ + 0² + 0 + 4

P(0) = 4

P(1) = 1³ + 1² + 1 + 4

P(1) = 1 + 1 + 5

P(1)  = 7

P(2) = 2³ + 2² + 2 + 4

P(2) = 8 + 4 + 6

P(2) = 18

P(- 1 ) = ( -1 )³ + ( - 1 )² + (- 1 ) + 4

P( - 1 ) = -1 + ( +1) - 1 + 4

P( - 1 ) = - 1 + 1 + 3

P( - 1 ) = 3

P(0)+ P( 1 ) + P(2) – 3P( - 1 ) = 4 + 7 + 18 - 3× 3 = 29 - 9 = 20