Question

Dado um triângulo de vértices (-1,1), (-3,1) e (-1,-3), o baricentro (ponto de encontro das medianas é:

a) (1/3), 0)
b) (1, 1/3)
c) (5/3, -1/3)
d) (-5/3, -1/3)
e) (-5/3, 1/3)

Answer 1

$\mathsf{x_{G}=\dfrac{x_{A}+x_{B}+x_{C}}{3}=\dfrac{-1-3-1}{3}=-\dfrac{5}{3}}$

$\mathsf{y_{G}=\dfrac{y_{A}+y_{B}+y_{C}}{3}=\dfrac{1+1-3}{3}=-\dfrac{1}{3}}$

$\huge\boxed{\boxed{\mathsf{G(-\dfrac{5}{3},-\dfrac{1}{3})}}}$

$\maltese~~\huge\boxed{\boxed{\mathsf{Alternativa\,d}}}$