Question

Dado sen x= 3/5, calcule o valor de
Cos x=
Tg x=
Cotg x=


Quero as respostas pfvvv

Answer 1

sen²x + cos²x = 1
(3/5)² + cos²x = 1
9/25 + cos²x = 1
cos²x = 1 -9/25
cos²x = 16/25
cos x = raiz de 16/25
cos x = 4/5

Tg = Sen/Cos
Tg = 3/5 / 4/5
Tg = 3/5 * 5/4
Tg = 15/20  :5
Tg = 3/4

Cotg x = 1 / 3/4
Cotg x = 1 * 4/3
Cotg x = 4/3