Question

Dado sen b = 5/12...qual o cos de b?

Answer 1

sen b² + cosb²  = 1



($\frac{5}{12}$)²  + cosb² = 1

cos b² = 1 - ($\frac{5}{12}$)²

cos b² = 1 - $\frac{25}{144}$

cos b ² = $\frac{119}{144}$

cos b = $\frac{ \sqrt{119}}{12}$