Question

dado o log2=0,301 calcule.

a) log 128 

b)log 6,4

c) log 0,625

 

Answer 1

 

 

a) log 128 = log 2^7 = 7log2 = 7.(0,301) = 2,101 

 

 

b)log 6,4 =  log (64/10) = log 64 - log 10

 

= log 2^6 - log 10 

= 6log2 - log10 

- 6(0,301) -1 

 

- 1,806 -1

 

= - 2,806

 

 

 

c) log 0,625   = log 625/1000  = log (5^4/ 10^3)

 

log5^4 - log10^3 

4log5 - 3log10

4log(10/2) - 3log10

4(log10 - log2) -3log10

4log10 -4log2-3log10

-4log2 +4log10-3log10

-4(0,301) +1

 

-1,204 + 1

 

-0,204

 

 

e fui