Question

Dado a pg (5,10,20..) calcule a razão dessa pg

Answer 1

Resposta:

$q=2$

Explicação passo-a-passo:

$PG=(a_1;a_2;a_3;\dots;a_n)=(5;10;20;\dots)\\\\ a_n=a_kq^{n-k}\ \therefore\ a_2=a_1q^{2-1}=a_1q\\\\ a_2=a_1q\ \therefore\ q=\dfrac{a_2}{a_1}=\dfrac{10}{5}\ \therefore\ q=2$