Question

Dadas as matrizes:
A= [ 3 2 ]
7 5
B= [ 1 1 ]
-1 1
Caucule A. B + -¹

Answer 1

[3 2] x [ 1 1 ] = [ 1 5 ] .+ [ 5 -2] = [ 6 3 ] <====r resp. falta elevarao quadrado 
[7 5] x [-1 1 ] = [ 2 12] + [-7 3] = [ -5 15] ou multipl. por ela mesma 

A^-1 
[3 2] = [ 5 -2 ] 
[7 5] = [ -7 3 ] 
. . . . ---------- 
. . . . . . 1

Answer 2

Resposta:

$\begin{pmatrix}6&3\\ -5&15\end{pmatrix}$

Explicação passo-a-passo:

$A\cdot \:B\:+\:A^{-1}$

$\begin{pmatrix}3&2\\ 7&5\end{pmatrix}\begin{pmatrix}1&1\\ -1&1\end{pmatrix}+\begin{pmatrix}3&2\\ 7&5\end{pmatrix}^{-1}$

$=\begin{pmatrix}3&2\\ 7&5\end{pmatrix}\begin{pmatrix}1&1\\ -1&1\end{pmatrix}+\begin{pmatrix}5&-2\\ -7&3\end{pmatrix}\\=\begin{pmatrix}1&5\\ 2&12\end{pmatrix}+\begin{pmatrix}5&-2\\ -7&3\end{pmatrix}\\=\begin{pmatrix}6&3\\ -5&15\end{pmatrix}$