Matemática, perguntado por eumirys, 1 ano atrás

Dadas as matrizes A = 0 4 -2
6 2 8

B= -3 6 9
12 -6 0

c= 0 -1 0
1 -1 2


Como efetuar 1/2.A-(1/3.b+c)

Soluções para a tarefa

Respondido por dexteright02
22
Como efetuar 1/2.A-[1/3.b+c]

 \frac{1}{2} *\left(\begin{array}{ccc}0&4&-2\\6&2&8\\\end{array}\right) - [  \frac{1}{3} *\left(\begin{array}{ccc}-3&6&9\\12&-6&0\\\end{array}\right)+\left(\begin{array}{ccc}0&-1&0\\1&-1&2\\\end{array}\right)]

= \left(\begin{array}{ccc}0&2&-1\\3&1&4\\\end{array}\right) - [\left(\begin{array}{ccc}-1&2&3\\4&-2&0\\\end{array}\right) + \left(\begin{array}{ccc}0&-1&0\\1&-1&2\\\end{array}\right)]

= \left(\begin{array}{ccc}0&2&-1\\3&1&4\\\end{array}\right) - [(\begin{array}{ccc}-1&1&3\\5&-3&2\\\end{array}\right))]

= \left(\begin{array}{ccc}0&2&-1\\3&1&4\\\end{array}\right) + [(\begin{array}{ccc}1&-1&-3\\-5&3&-2\\\end{array}\right))]

= \boxed{\boxed{\left(\begin{array}{ccc}1&1&-4\\-2&4&2\\\end{array}\right)}}\end{array}}\qquad\quad\checkmark


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