Question

Dadas as funções f(x) = 5-2x e g(x) = 3x^2-1, calcular f´(1)+g´(1)

Answer 1

$f(x) = 5-2x ; g(x) = 3x^2-1\\\\ f(1)+g(1)\\\\\\(5-2*1)+(3* 1^{2} -1)\to\\\\(5-2)+(3*1-1)\to\\\\ 3+3-1=5$


Letra B)5.

Answer 2

Resposta:

4

Explicação passo-a-passo:

$\lim_{h \to \ 0$ $\frac{f(a+h)-f(a)}{h}$

$\lim_{h \to \ 0$ $\frac{5-2(1+h)-(5-2*1)}{h}$

$\lim_{h \to \ 0$ $\frac{5-2-2h-3}{h}$

$\lim_{h \to \ 0$ $\frac{h(-2-h)}{h}$

$\lim_{h \to \ 0$ $\(-2-h) </p><p>f'(1)= -2</p><p>[tex]\lim_{h \to \ 0$ $\frac{f(a+h)-f(a)}{h}$

$\lim_{h \to \ 0$ $\frac{3(1+h)^2-1-(3-1)}{h}$

$\lim_{h \to \ 0$ $\frac{3(1+2h+h^2)-1-2}{h}$

$\lim_{h \to \ 0$ $\frac{3+6h+h^2 -3}{h}$

$\lim_{h \to \ 0$ $\frac{h(6+h)}{h}$

$\lim_{h \to \ 0$ [tex]\(6+h)

g'(1)= 6

g'(1)+f'(1)= -2+6 =4