Question

dada f(x)= raiz cubica de x . qual o valor de f(8) +f'(1) sobre 3

Answer 1

f(x)=∛x 

f(8)=∛2³=2

f'=(1/3)* x^(1/3-1)

f'(x)=(1/3)*x^(-2/3)  =(1/3)* (1/∛x²) =1/(3∛x²)
f'(1)=1/3

 f(8) +f'(1) sobre 3 = 2  + (1/3)/3 ===2+1/9 =19/9