Dada as matrizes:
![A = \left[\begin{array}{ccc}2&3\\-1&5\end{array}\right]](https://tex.z-dn.net/?f=A+%3D++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26amp%3B3%5C%5C-1%26amp%3B5%5Cend%7Barray%7D%5Cright%5D+ "A = \left[\begin{array}{ccc}2&3\\-1&5\end{array}\right]")
![B= \left[\begin{array}{ccc}1&-3\\-2&-4\end{array}\right]](https://tex.z-dn.net/?f=B%3D++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26amp%3B-3%5C%5C-2%26amp%3B-4%5Cend%7Barray%7D%5Cright%5D+ "B= \left[\begin{array}{ccc}1&-3\\-2&-4\end{array}\right]")
determine o produto BA:
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Olá
Multiplicação de matrizes são linhas por colunas
![B \left[\begin{array}{ccc}1&-3\\-2&-4\\\end{array}\right] ~\cdot A \left[\begin{array}{ccc}2&3\\-1&5\\\end{array}\right] \\ \\ \\ BA=\left[\begin{array}{ccc}((1\cdot2)+(-3\cdot-1))~~~&((1\cdot3)+(-3\cdot5))\\((-2\cdot2)+(-4\cdot-1))~~~&((-2\cdot3)+(-4\cdot5))\\\end{array}\right] \\ \\ \\ BA= \left[\begin{array}{ccc}(2+3)~~&(3-15)\\(-4+4)&(-6-20)\\\end{array}\right] \\ \\ \\ \boxed{\boxed{ BA= \left[\begin{array}{ccc}5&-12\\0&-26\\\end{array}\right] }}](https://tex.z-dn.net/?f=B++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26amp%3B-3%5C%5C-2%26amp%3B-4%5C%5C%5Cend%7Barray%7D%5Cright%5D+%7E%5Ccdot+A++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26amp%3B3%5C%5C-1%26amp%3B5%5C%5C%5Cend%7Barray%7D%5Cright%5D++%5C%5C++%5C%5C++%5C%5C+BA%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%28%281%5Ccdot2%29%2B%28-3%5Ccdot-1%29%29%7E%7E%7E%26amp%3B%28%281%5Ccdot3%29%2B%28-3%5Ccdot5%29%29%5C%5C%28%28-2%5Ccdot2%29%2B%28-4%5Ccdot-1%29%29%7E%7E%7E%26amp%3B%28%28-2%5Ccdot3%29%2B%28-4%5Ccdot5%29%29%5C%5C%5Cend%7Barray%7D%5Cright%5D++%5C%5C++%5C%5C++%5C%5C+BA%3D++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%282%2B3%29%7E%7E%26amp%3B%283-15%29%5C%5C%28-4%2B4%29%26amp%3B%28-6-20%29%5C%5C%5Cend%7Barray%7D%5Cright%5D++%5C%5C++%5C%5C++%5C%5C+%5Cboxed%7B%5Cboxed%7B+BA%3D+%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%26amp%3B-12%5C%5C0%26amp%3B-26%5C%5C%5Cend%7Barray%7D%5Cright%5D+%7D%7D "B \left[\begin{array}{ccc}1&-3\\-2&-4\\\end{array}\right] ~\cdot A \left[\begin{array}{ccc}2&3\\-1&5\\\end{array}\right] \\ \\ \\ BA=\left[\begin{array}{ccc}((1\cdot2)+(-3\cdot-1))~~~&((1\cdot3)+(-3\cdot5))\\((-2\cdot2)+(-4\cdot-1))~~~&((-2\cdot3)+(-4\cdot5))\\\end{array}\right] \\ \\ \\ BA= \left[\begin{array}{ccc}(2+3)~~&(3-15)\\(-4+4)&(-6-20)\\\end{array}\right] \\ \\ \\ \boxed{\boxed{ BA= \left[\begin{array}{ccc}5&-12\\0&-26\\\end{array}\right] }}")
Multiplicação de matrizes são linhas por colunas
rodrigobaroni:
muito obrigado mesmo ajudou demais
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