Question

dada as matrizes calcule
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Answer 1

Resposta:

letra b)

Explicação passo a passo:

$A = \left(\begin{array}{ccc}2&-3&1\\7&2&-5\\\end{array}\right) ; B = \left[\begin{array}{ccc}1&3&4\\3&-2&-1\end{array}\right]; C = \left[\begin{array}{ccc}9&1\\-2&5\\0&-7\\\end{array}\right]\\\\\\A-B = \left(\begin{array}{ccc}2&-3&1\\7&2&-5\\\end{array}\right)-\left[\begin{array}{ccc}1&3&4\\3&-2&-1\end{array}\right] = \left[\begin{array}{ccc}2-1&-3-3&1-4\\7-3&2-(-2)&-5-(-1)\\\end{array}\right]\\\\\\ = \left[\begin{array}{ccc}1&-6&-3\\4&4&-4\\\end{array}\right]$

$B\cdot C = \left[\begin{array}{ccc}1&3&4\\3&-2&-1\end{array}\right]\cdot \left[\begin{array}{ccc}9&1\\-2&5\\0&-7\end{array}\right] = \left[\begin{array}{ccc}3&-12\\31&0\end{array}\right]$

$3A+B = \left(\begin{array}{ccc}6&-9&3\\21&6&-15\\\end{array}\right) +\left[\begin{array}{ccc}1&3&4\\3&-2&-1\\\end{array}\right] = \left[\begin{array}{ccc}7&-6&7\\24&4&-16\\\end{array}\right]$