Question

Dada as funções F(x)=3x-4 e g(x)=x²-3x+7, calcule:

A) F(1)
B)F(-2)
C) F(-5)
D) G(0)
E) G(-2)
F) F(3)-g(4)

Answer 1

a) F(x)=3x-4 > f(1)= 3(1) - 4 > f(1)= 3 -4 >> f(1)= -1

b) F(-2)= 3(-2) -4 > f(-2)= -6 -4 >> f(-2)= -10

c) F(-5)= 3(-5) -4 > f(-5)= -15 -4 >> f(-5)= -19

d) G(x)= x^2 -3x +7 > g(0)= 0^2 -3(0) +7 >> g(0)=7

e) G(-2)= (-2)^2 -3(-2) +7 > g(-2)= -4 + 6 +7 >> g(-2)= 9

f) F(3) - g(4) = 4^2 +(3.3-(-3.4)) + (-4-(+7)) > F(3) - g(4) = 16 +(9+12) -11 > F(3) - g(4) = 16 + 21 - 11 >> F(3) - g(4) = 26