Question

dada a progressão 5,16,27,38..., calcule: o 20° termo​

Answer 1

Termo geral da PA em função de um termo qualquer

$\boxed{\boxed{\boxed{\mathsf{a_{n}=a_{p}+(n-p)r}}}}$

$\mathsf{a_{20}=a_{4}+16r}\\\mathsf{a_{20}=38+16.11}\\\mathsf{a_{20}=38+176}$

$\huge\boxed{\boxed{\boxed{\mathsf{a_{20}=214}}}}$