Question

dada a pg (1,2...,1024) calcule a soma dos termos

Answer 1

a1 = 1
an = 1024 = 2^10
q = 2

an = a1.q^(n - 1)
2^10 = 1.2^(n - 1)
2^10 = 2^(n - 1)
n - 1 = 10
n = 10 + 1
n = 11

Sn = a1.(qⁿ - 1)/(q - 1)
Sn = 1.(2¹¹ - 1)/(2 - 1)
Sn = 2¹¹ - 1
Sn = 2048 - 1
Sn = 2047